1311131211311 has 2 divisors, whose sum is σ = 1311131211312. Its totient is φ = 1311131211310.

The previous prime is 1311131211301. The next prime is 1311131211337. The reversal of 1311131211311 is 1131121311131.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1311131211311 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1311131211301) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655565605655 + 655565605656.

It is an arithmetic number, because the mean of its divisors is an integer number (655565605656).

Almost surely, 2^{1311131211311} is an apocalyptic number.

1311131211311 is a deficient number, since it is larger than the sum of its proper divisors (1).

1311131211311 is an equidigital number, since it uses as much as digits as its factorization.

1311131211311 is an evil number, because the sum of its binary digits is even.

The product of its digits is 54, while the sum is 20.

Adding to 1311131211311 its reverse (1131121311131), we get a palindrome (2442252522442).

The spelling of 1311131211311 in words is "one trillion, three hundred eleven billion, one hundred thirty-one million, two hundred eleven thousand, three hundred eleven".