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131113201001 = 209476259283
BaseRepresentation
bin111101000011011110…
…1001010110101101001
3110112102111121201022112
41322012331022311221
54122004434413001
6140122122532105
712321051551216
oct1720675126551
9415374551275
10131113201001
1150671a90562
12214b1667035
13c4966c8053
1464bb282b0d
153625955cbb
hex1e86f4ad69

131113201001 has 4 divisors (see below), whose sum is σ = 131119481232. Its totient is φ = 131106920772.

The previous prime is 131113200989. The next prime is 131113201061. The reversal of 131113201001 is 100102311131.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 131113201001 - 222 = 131109006697 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131113201061) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3108695 + ... + 3150588.

It is an arithmetic number, because the mean of its divisors is an integer number (32779870308).

Almost surely, 2131113201001 is an apocalyptic number.

It is an amenable number.

131113201001 is a deficient number, since it is larger than the sum of its proper divisors (6280231).

131113201001 is an equidigital number, since it uses as much as digits as its factorization.

131113201001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6280230.

The product of its (nonzero) digits is 18, while the sum is 14.

Adding to 131113201001 its reverse (100102311131), we get a palindrome (231215512132).

The spelling of 131113201001 in words is "one hundred thirty-one billion, one hundred thirteen million, two hundred one thousand, one".

Divisors: 1 20947 6259283 131113201001