13111320113 has 4 divisors (see below), whose sum is σ = 13199315700. Its totient is φ = 13023324528.

The previous prime is 13111320059. The next prime is 13111320119. The reversal of 13111320113 is 31102311131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 5599977889 + 7511342224 = 74833^2 + 86668^2 .

It is a cyclic number.

It is not a de Polignac number, because 13111320113 - 2⁸ = 13111319857 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13111320091 and 13111320100.

It is not an unprimeable number, because it can be changed into a prime (13111320119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 43997570 + ... + 43997867.

It is an arithmetic number, because the mean of its divisors is an integer number (3299828925).

Almost surely, 2^13111320113 is an apocalyptic number.

It is an amenable number.

13111320113 is a deficient number, since it is larger than the sum of its proper divisors (87995587).

13111320113 is an equidigital number, since it uses as much as digits as its factorization.

13111320113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 87995586.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 13111320113 its reverse (31102311131), we get a palindrome (44213631244).

The spelling of 13111320113 in words is "thirteen billion, one hundred eleven million, three hundred twenty thousand, one hundred thirteen".