13111321034321 has 2 divisors, whose sum is σ = 13111321034322. Its totient is φ = 13111321034320.

The previous prime is 13111321034257. The next prime is 13111321034323. The reversal of 13111321034321 is 12343012311131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8511432814096 + 4599888220225 = 2917436^2 + 2144735^2 .

It is an emirp because it is prime and its reverse (12343012311131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13111321034321 - 2⁶ = 13111321034257 is a prime.

It is a super-3 number, since 3×13111321034321³ (a number of 40 digits) contains 333 as substring.

Together with 13111321034323, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (13111321034323) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555660517160 + 6555660517161.

It is an arithmetic number, because the mean of its divisors is an integer number (6555660517161).

Almost surely, 2^{13111321034321} is an apocalyptic number.

It is an amenable number.

13111321034321 is a deficient number, since it is larger than the sum of its proper divisors (1).

13111321034321 is an equidigital number, since it uses as much as digits as its factorization.

13111321034321 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1296, while the sum is 26.

Adding to 13111321034321 its reverse (12343012311131), we get a palindrome (25454333345452).

The spelling of 13111321034321 in words is "thirteen trillion, one hundred eleven billion, three hundred twenty-one million, thirty-four thousand, three hundred twenty-one".