1311132221031 has 4 divisors (see below), whose sum is σ = 1748176294712. Its totient is φ = 874088147352.

The previous prime is 1311132221011. The next prime is 1311132221033. The reversal of 1311132221031 is 1301222311131.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 1311132221031 - 2¹³ = 1311132212839 is a prime.

It is a super-2 number, since 2×1311132221031² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1311132220989 and 1311132221007.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1311132221033) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 218522036836 + ... + 218522036841.

It is an arithmetic number, because the mean of its divisors is an integer number (437044073678).

Almost surely, 2^{1311132221031} is an apocalyptic number.

1311132221031 is a deficient number, since it is larger than the sum of its proper divisors (437044073681).

1311132221031 is an equidigital number, since it uses as much as digits as its factorization.

1311132221031 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 437044073680.

The product of its (nonzero) digits is 216, while the sum is 21.

Adding to 1311132221031 its reverse (1301222311131), we get a palindrome (2612354532162).

The spelling of 1311132221031 in words is "one trillion, three hundred eleven billion, one hundred thirty-two million, two hundred twenty-one thousand, thirty-one".