13111322300023 has 2 divisors, whose sum is σ = 13111322300024. Its totient is φ = 13111322300022.

The previous prime is 13111322299991. The next prime is 13111322300029. The reversal of 13111322300023 is 32000322311131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13111322300023 - 2⁵ = 13111322299991 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13111322299967 and 13111322300003.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13111322300029) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555661150011 + 6555661150012.

It is an arithmetic number, because the mean of its divisors is an integer number (6555661150012).

Almost surely, 2^{13111322300023} is an apocalyptic number.

13111322300023 is a deficient number, since it is larger than the sum of its proper divisors (1).

13111322300023 is an equidigital number, since it uses as much as digits as its factorization.

13111322300023 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 648, while the sum is 22.

Adding to 13111322300023 its reverse (32000322311131), we get a palindrome (45111644611154).

The spelling of 13111322300023 in words is "thirteen trillion, one hundred eleven billion, three hundred twenty-two million, three hundred thousand, twenty-three".