Base | Representation |
---|---|
bin | 111101000011011111… |
… | …0011001010100000001 |
3 | 110112102112020001020102 |
4 | 1322012332121110001 |
5 | 4122010030204213 |
6 | 140122133452145 |
7 | 12321054360305 |
oct | 1720676312401 |
9 | 415375201212 |
10 | 131113522433 |
11 | 50672190003 |
12 | 214b17a1055 |
13 | c4967ab44a |
14 | 64bb327d05 |
15 | 36259bb158 |
hex | 1e86f99501 |
131113522433 has 12 divisors (see below), whose sum is σ = 138423403620. Its totient is φ = 124171543296.
The previous prime is 131113522429. The next prime is 131113522447. The reversal of 131113522433 is 334225311131.
It can be written as a sum of positive squares in 2 ways, for example, as 123111862129 + 8001660304 = 350873^2 + 89452^2 .
It is not a de Polignac number, because 131113522433 - 22 = 131113522429 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 131113522396 and 131113522405.
It is not an unprimeable number, because it can be changed into a prime (131113522403) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 1056341 + ... + 1173917.
It is an arithmetic number, because the mean of its divisors is an integer number (11535283635).
Almost surely, 2131113522433 is an apocalyptic number.
It is an amenable number.
131113522433 is a deficient number, since it is larger than the sum of its proper divisors (7309881187).
131113522433 is a wasteful number, since it uses less digits than its factorization.
131113522433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 120704 (or 120685 counting only the distinct ones).
The product of its digits is 6480, while the sum is 29.
Adding to 131113522433 its reverse (334225311131), we get a palindrome (465338833564).
The spelling of 131113522433 in words is "one hundred thirty-one billion, one hundred thirteen million, five hundred twenty-two thousand, four hundred thirty-three".
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