1311140454033 has 4 divisors (see below), whose sum is σ = 1748187272048. Its totient is φ = 874093636020.

The previous prime is 1311140453899. The next prime is 1311140454059. The reversal of 1311140454033 is 3304540411131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 1311140454033 - 2¹⁰ = 1311140453009 is a prime.

It is a super-2 number, since 2×1311140454033² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1311140453033) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 218523409003 + ... + 218523409008.

It is an arithmetic number, because the mean of its divisors is an integer number (437046818012).

Almost surely, 2^{1311140454033} is an apocalyptic number.

It is an amenable number.

1311140454033 is a deficient number, since it is larger than the sum of its proper divisors (437046818015).

1311140454033 is an equidigital number, since it uses as much as digits as its factorization.

1311140454033 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 437046818014.

The product of its (nonzero) digits is 8640, while the sum is 30.

Adding to 1311140454033 its reverse (3304540411131), we get a palindrome (4615680865164).

The spelling of 1311140454033 in words is "one trillion, three hundred eleven billion, one hundred forty million, four hundred fifty-four thousand, thirty-three".