13111411430133 has 6 divisors (see below), whose sum is σ = 18938705399094. Its totient is φ = 8740940953416.

The previous prime is 13111411430107. The next prime is 13111411430137. The reversal of 13111411430133 is 33103411411131.

13111411430133 is a `hidden beast` number, since 1 + 3 + 111 + 411 + 4 + 3 + 0 + 133 = 666.

It can be written as a sum of positive squares in only one way, i.e., 10544872860369 + 2566538569764 = 3247287^2 + 1602042^2 .

It is a de Polignac number, because none of the positive numbers 2^k-13111411430133 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13111411430097 and 13111411430106.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13111411430137) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 728411746110 + ... + 728411746127.

It is an arithmetic number, because the mean of its divisors is an integer number (3156450899849).

Almost surely, 2^{13111411430133} is an apocalyptic number.

It is an amenable number.

13111411430133 is a deficient number, since it is larger than the sum of its proper divisors (5827293968961).

13111411430133 is a wasteful number, since it uses less digits than its factorization.

13111411430133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1456823492243 (or 1456823492240 counting only the distinct ones).

The product of its (nonzero) digits is 1296, while the sum is 27.

Adding to 13111411430133 its reverse (33103411411131), we get a palindrome (46214822841264).

The spelling of 13111411430133 in words is "thirteen trillion, one hundred eleven billion, four hundred eleven million, four hundred thirty thousand, one hundred thirty-three".