13111420121 has 4 divisors (see below), whose sum is σ = 13416336912. Its totient is φ = 12806503332.

The previous prime is 13111420099. The next prime is 13111420129. The reversal of 13111420121 is 12102411131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13111420121 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13111420121.

It is not an unprimeable number, because it can be changed into a prime (13111420129) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 152458331 + ... + 152458416.

It is an arithmetic number, because the mean of its divisors is an integer number (3354084228).

Almost surely, 2^13111420121 is an apocalyptic number.

It is an amenable number.

13111420121 is a deficient number, since it is larger than the sum of its proper divisors (304916791).

13111420121 is an equidigital number, since it uses as much as digits as its factorization.

13111420121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 304916790.

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 13111420121 its reverse (12102411131), we get a palindrome (25213831252).

The spelling of 13111420121 in words is "thirteen billion, one hundred eleven million, four hundred twenty thousand, one hundred twenty-one".