13111431433 has 8 divisors (see below), whose sum is σ = 13192267968. Its totient is φ = 13030653264.

The previous prime is 13111431419. The next prime is 13111431457. The reversal of 13111431433 is 33413411131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13111431433 - 2⁵ = 13111431401 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13111431398 and 13111431407.

It is not an unprimeable number, because it can be changed into a prime (13111431413) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 489166 + ... + 515272.

It is an arithmetic number, because the mean of its divisors is an integer number (1649033496).

Almost surely, 2^13111431433 is an apocalyptic number.

It is an amenable number.

13111431433 is a deficient number, since it is larger than the sum of its proper divisors (80836535).

13111431433 is a wasteful number, since it uses less digits than its factorization.

13111431433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 29183.

The product of its digits is 1296, while the sum is 25.

Adding to 13111431433 its reverse (33413411131), we get a palindrome (46524842564).

The spelling of 13111431433 in words is "thirteen billion, one hundred eleven million, four hundred thirty-one thousand, four hundred thirty-three".