13111432084633 has 2 divisors, whose sum is σ = 13111432084634. Its totient is φ = 13111432084632.

The previous prime is 13111432084613. The next prime is 13111432084693. The reversal of 13111432084633 is 33648023411131.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13054441026649 + 56991057984 = 3613093^2 + 238728^2 .

It is an emirp because it is prime and its reverse (33648023411131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13111432084633 - 2¹⁷ = 13111431953561 is a prime.

It is not a weakly prime, because it can be changed into another prime (13111432084613) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555716042316 + 6555716042317.

It is an arithmetic number, because the mean of its divisors is an integer number (6555716042317).

Almost surely, 2^{13111432084633} is an apocalyptic number.

It is an amenable number.

13111432084633 is a deficient number, since it is larger than the sum of its proper divisors (1).

13111432084633 is an equidigital number, since it uses as much as digits as its factorization.

13111432084633 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 124416, while the sum is 40.

Adding to 13111432084633 its reverse (33648023411131), we get a palindrome (46759455495764).

The spelling of 13111432084633 in words is "thirteen trillion, one hundred eleven billion, four hundred thirty-two million, eighty-four thousand, six hundred thirty-three".