Base | Representation |
---|---|
bin | 10011000101000110001… |
… | …110100011001001110001 |
3 | 11122100021211022220211202 |
4 | 103011012032203021301 |
5 | 132440210132310101 |
6 | 2442155250020545 |
7 | 163504231456364 |
oct | 23050616431161 |
9 | 4570254286752 |
10 | 1311143244401 |
11 | 4660641a8691 |
12 | 192137277755 |
13 | 968428c6a93 |
14 | 476614a60db |
15 | 2418c35c36b |
hex | 131463a3271 |
1311143244401 has 4 divisors (see below), whose sum is σ = 1380150783600. Its totient is φ = 1242135705204.
The previous prime is 1311143244343. The next prime is 1311143244403. The reversal of 1311143244401 is 1044423411131.
It is a happy number.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 1311143244401 - 234 = 1293963375217 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1311143244403) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 34503769571 + ... + 34503769608.
It is an arithmetic number, because the mean of its divisors is an integer number (345037695900).
Almost surely, 21311143244401 is an apocalyptic number.
It is an amenable number.
1311143244401 is a deficient number, since it is larger than the sum of its proper divisors (69007539199).
1311143244401 is an equidigital number, since it uses as much as digits as its factorization.
1311143244401 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 69007539198.
The product of its (nonzero) digits is 4608, while the sum is 29.
Adding to 1311143244401 its reverse (1044423411131), we get a palindrome (2355566655532).
The spelling of 1311143244401 in words is "one trillion, three hundred eleven billion, one hundred forty-three million, two hundred forty-four thousand, four hundred one".
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