Base | Representation |
---|---|
bin | 1011111011001011111001… |
… | …0100000111110001110101 |
3 | 1201102102220022121012202222 |
4 | 2332302332110013301311 |
5 | 3204304203340230143 |
6 | 43515150443212125 |
7 | 2522161351532564 |
oct | 276627624076165 |
9 | 51372808535688 |
10 | 13111433133173 |
11 | 41a5589209a91 |
12 | 1579100517045 |
13 | 741531064bcb |
14 | 33484d6a3bdb |
15 | 17b0d24bb768 |
hex | becbe507c75 |
13111433133173 has 2 divisors, whose sum is σ = 13111433133174. Its totient is φ = 13111433133172.
The previous prime is 13111433133167. The next prime is 13111433133233. The reversal of 13111433133173 is 37133133411131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12939322654129 + 172110479044 = 3597127^2 + 414862^2 .
It is a cyclic number.
It is not a de Polignac number, because 13111433133173 - 242 = 8713386622069 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13111433133133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555716566586 + 6555716566587.
It is an arithmetic number, because the mean of its divisors is an integer number (6555716566587).
Almost surely, 213111433133173 is an apocalyptic number.
It is an amenable number.
13111433133173 is a deficient number, since it is larger than the sum of its proper divisors (1).
13111433133173 is an equidigital number, since it uses as much as digits as its factorization.
13111433133173 is an evil number, because the sum of its binary digits is even.
The product of its digits is 20412, while the sum is 35.
The spelling of 13111433133173 in words is "thirteen trillion, one hundred eleven billion, four hundred thirty-three million, one hundred thirty-three thousand, one hundred seventy-three".
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