13111434223301 has 4 divisors (see below), whose sum is σ = 13111441480992. Its totient is φ = 13111426965612.

The previous prime is 13111434223291. The next prime is 13111434223331. The reversal of 13111434223301 is 10332243411131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13111434223301 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13111434223331) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1456046 + ... + 5323808.

It is an arithmetic number, because the mean of its divisors is an integer number (3277860370248).

Almost surely, 2^{13111434223301} is an apocalyptic number.

It is an amenable number.

13111434223301 is a deficient number, since it is larger than the sum of its proper divisors (7257691).

13111434223301 is an equidigital number, since it uses as much as digits as its factorization.

13111434223301 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7257690.

The product of its (nonzero) digits is 5184, while the sum is 29.

Adding to 13111434223301 its reverse (10332243411131), we get a palindrome (23443677634432).

The spelling of 13111434223301 in words is "thirteen trillion, one hundred eleven billion, four hundred thirty-four million, two hundred twenty-three thousand, three hundred one".