13111434244021 has 4 divisors (see below), whose sum is σ = 13390400930112. Its totient is φ = 12832467557932.

The previous prime is 13111434244019. The next prime is 13111434244037. The reversal of 13111434244021 is 12044243411131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13111434244021 - 2¹ = 13111434244019 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13111434244091) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 139483342975 + ... + 139483343068.

It is an arithmetic number, because the mean of its divisors is an integer number (3347600232528).

Almost surely, 2^{13111434244021} is an apocalyptic number.

It is an amenable number.

13111434244021 is a deficient number, since it is larger than the sum of its proper divisors (278966686091).

13111434244021 is an equidigital number, since it uses as much as digits as its factorization.

13111434244021 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 278966686090.

The product of its (nonzero) digits is 9216, while the sum is 31.

Adding to 13111434244021 its reverse (12044243411131), we get a palindrome (25155677655152).

The spelling of 13111434244021 in words is "thirteen trillion, one hundred eleven billion, four hundred thirty-four million, two hundred forty-four thousand, twenty-one".