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131115103 = 718730729
BaseRepresentation
bin1111101000010…
…10100001011111
3100010201100002221
413310022201133
5232031140403
621002130211
73151313530
oct764124137
9303640087
10131115103
1168013799
1237ab0967
1321219202
14135b0687
15b79ddbd
hex7d0a85f

131115103 has 4 divisors (see below), whose sum is σ = 149845840. Its totient is φ = 112384368.

The previous prime is 131115097. The next prime is 131115109. The reversal of 131115103 is 301511131.

131115103 is nontrivially palindromic in base 2.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (131115097) and next prime (131115109).

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-131115103 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131115109) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9365358 + ... + 9365371.

It is an arithmetic number, because the mean of its divisors is an integer number (37461460).

Almost surely, 2131115103 is an apocalyptic number.

131115103 is a deficient number, since it is larger than the sum of its proper divisors (18730737).

131115103 is an equidigital number, since it uses as much as digits as its factorization.

131115103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 18730736.

The product of its (nonzero) digits is 45, while the sum is 16.

The square root of 131115103 is about 11450.5503361192. The cubic root of 131115103 is about 508.0240122880.

Adding to 131115103 its reverse (301511131), we get a palindrome (432626234).

The spelling of 131115103 in words is "one hundred thirty-one million, one hundred fifteen thousand, one hundred three".

Divisors: 1 7 18730729 131115103