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131115155225317 is a prime number
BaseRepresentation
bin11101110011111110100000…
…010000000111101011100101
3122012020111010121022021021221
4131303332200100013223211
5114141142314214202232
61142505245404340341
736421520526550414
oct3563764020075345
9565214117267257
10131115155225317
1138860696a6131a
1212856bb42446b1
13582114c0b78b3
14245401633547b
1510259157c1897
hex773fa0407ae5

131115155225317 has 2 divisors, whose sum is σ = 131115155225318. Its totient is φ = 131115155225316.

The previous prime is 131115155225279. The next prime is 131115155225323. The reversal of 131115155225317 is 713522551511131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 81082082784481 + 50033072440836 = 9004559^2 + 7073406^2 .

It is an emirp because it is prime and its reverse (713522551511131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 131115155225317 - 219 = 131115154701029 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131115155225617) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65557577612658 + 65557577612659.

It is an arithmetic number, because the mean of its divisors is an integer number (65557577612659).

Almost surely, 2131115155225317 is an apocalyptic number.

It is an amenable number.

131115155225317 is a deficient number, since it is larger than the sum of its proper divisors (1).

131115155225317 is an equidigital number, since it uses as much as digits as its factorization.

131115155225317 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 157500, while the sum is 43.

The spelling of 131115155225317 in words is "one hundred thirty-one trillion, one hundred fifteen billion, one hundred fifty-five million, two hundred twenty-five thousand, three hundred seventeen".