Base | Representation |
---|---|
bin | 11101110011111110100010… |
… | …111111111101010101101111 |
3 | 122012020111020211001010201122 |
4 | 131303332202333331111233 |
5 | 114141142413014222203 |
6 | 1142505254132331155 |
7 | 36421521626422214 |
oct | 3563764277752557 |
9 | 565214224033648 |
10 | 131115201320303 |
11 | 3886070aa85152 |
12 | 12857007773abb |
13 | 5821158806735 |
14 | 245401c4d3b0b |
15 | 1025919879538 |
hex | 773fa2ffd56f |
131115201320303 has 4 divisors (see below), whose sum is σ = 131141943157008. Its totient is φ = 131088459483600.
The previous prime is 131115201320263. The next prime is 131115201320309. The reversal of 131115201320303 is 303023102511131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 131115201320303 - 210 = 131115201319279 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131115201320309) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13370910998 + ... + 13370920803.
It is an arithmetic number, because the mean of its divisors is an integer number (32785485789252).
Almost surely, 2131115201320303 is an apocalyptic number.
131115201320303 is a deficient number, since it is larger than the sum of its proper divisors (26741836705).
131115201320303 is an equidigital number, since it uses as much as digits as its factorization.
131115201320303 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 26741836704.
The product of its (nonzero) digits is 1620, while the sum is 26.
Adding to 131115201320303 its reverse (303023102511131), we get a palindrome (434138303831434).
The spelling of 131115201320303 in words is "one hundred thirty-one trillion, one hundred fifteen billion, two hundred one million, three hundred twenty thousand, three hundred three".
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