Base | Representation |
---|---|
bin | 11101110011111110100100… |
… | …110110111010011001101111 |
3 | 122012020111022222201101220102 |
4 | 131303332210312322121233 |
5 | 114141142444010102112 |
6 | 1142505301204541315 |
7 | 36421522455446105 |
oct | 3563764466723157 |
9 | 565214288641812 |
10 | 131115232503407 |
11 | 38860726643509 |
12 | 128570160b183b |
13 | 5821162104089 |
14 | 24540226cdc75 |
15 | 102591c488bc2 |
hex | 773fa4dba66f |
131115232503407 has 2 divisors, whose sum is σ = 131115232503408. Its totient is φ = 131115232503406.
The previous prime is 131115232503301. The next prime is 131115232503469. The reversal of 131115232503407 is 704305232511131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131115232503407 - 224 = 131115215726191 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131115232509407) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65557616251703 + 65557616251704.
It is an arithmetic number, because the mean of its divisors is an integer number (65557616251704).
Almost surely, 2131115232503407 is an apocalyptic number.
131115232503407 is a deficient number, since it is larger than the sum of its proper divisors (1).
131115232503407 is an equidigital number, since it uses as much as digits as its factorization.
131115232503407 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 75600, while the sum is 38.
The spelling of 131115232503407 in words is "one hundred thirty-one trillion, one hundred fifteen billion, two hundred thirty-two million, five hundred three thousand, four hundred seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.067 sec. • engine limits •