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1311154888753 is a prime number
BaseRepresentation
bin10011000101000110111…
…010111110000000110001
311122100022122020111220001
4103011012322332000301
5132440221122420003
62442200343350001
7163504432445053
oct23050672760061
94570278214801
101311154888753
1146606a831216
1219213b152301
1396845142c28
1447662c578d3
152418d3ac61d
hex13146ebe031

1311154888753 has 2 divisors, whose sum is σ = 1311154888754. Its totient is φ = 1311154888752.

The previous prime is 1311154888727. The next prime is 1311154888787. The reversal of 1311154888753 is 3578884511131.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1102115733489 + 209039155264 = 1049817^2 + 457208^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1311154888753 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1311154888694 and 1311154888703.

It is not a weakly prime, because it can be changed into another prime (1311154888453) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655577444376 + 655577444377.

It is an arithmetic number, because the mean of its divisors is an integer number (655577444377).

Almost surely, 21311154888753 is an apocalyptic number.

It is an amenable number.

1311154888753 is a deficient number, since it is larger than the sum of its proper divisors (1).

1311154888753 is an equidigital number, since it uses as much as digits as its factorization.

1311154888753 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 3225600, while the sum is 55.

The spelling of 1311154888753 in words is "one trillion, three hundred eleven billion, one hundred fifty-four million, eight hundred eighty-eight thousand, seven hundred fifty-three".