Base | Representation |
---|---|
bin | 10011000101000111010… |
… | …010010111001010111101 |
3 | 11122100100001210001220122 |
4 | 103011013102113022331 |
5 | 132440224210133432 |
6 | 2442201123024325 |
7 | 163504535535503 |
oct | 23050722271275 |
9 | 4570301701818 |
10 | 1311161021117 |
11 | 46607323a592 |
12 | 19214120b0a5 |
13 | 968464ac24c |
14 | 476639b2673 |
15 | 2418dbbe612 |
hex | 131474972bd |
1311161021117 has 2 divisors, whose sum is σ = 1311161021118. Its totient is φ = 1311161021116.
The previous prime is 1311161021081. The next prime is 1311161021179. The reversal of 1311161021117 is 7111201611131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1257064773721 + 54096247396 = 1121189^2 + 232586^2 .
It is an emirp because it is prime and its reverse (7111201611131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1311161021117 - 222 = 1311156826813 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1311161021917) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655580510558 + 655580510559.
It is an arithmetic number, because the mean of its divisors is an integer number (655580510559).
Almost surely, 21311161021117 is an apocalyptic number.
It is an amenable number.
1311161021117 is a deficient number, since it is larger than the sum of its proper divisors (1).
1311161021117 is an equidigital number, since it uses as much as digits as its factorization.
1311161021117 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 252, while the sum is 26.
Adding to 1311161021117 its reverse (7111201611131), we get a palindrome (8422362632248).
The spelling of 1311161021117 in words is "one trillion, three hundred eleven billion, one hundred sixty-one million, twenty-one thousand, one hundred seventeen".
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