Base | Representation |
---|---|
bin | 100111000100111… |
… | …0101001100101001 |
3 | 10101101020212022111 |
4 | 1032021311030221 |
5 | 10141131400131 |
6 | 334035322321 |
7 | 44331005434 |
oct | 11611651451 |
9 | 3341225274 |
10 | 1311200041 |
11 | 613157aa8 |
12 | 3071503a1 |
13 | 17b859b18 |
14 | c61d881b |
15 | 7a1a3ab1 |
hex | 4e275329 |
1311200041 has 2 divisors, whose sum is σ = 1311200042. Its totient is φ = 1311200040.
The previous prime is 1311200003. The next prime is 1311200047. The reversal of 1311200041 is 1400021131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1307184025 + 4016016 = 36155^2 + 2004^2 .
It is a cyclic number.
It is not a de Polignac number, because 1311200041 - 221 = 1309102889 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1311199994 and 1311200030.
It is not a weakly prime, because it can be changed into another prime (1311200047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655600020 + 655600021.
It is an arithmetic number, because the mean of its divisors is an integer number (655600021).
Almost surely, 21311200041 is an apocalyptic number.
It is an amenable number.
1311200041 is a deficient number, since it is larger than the sum of its proper divisors (1).
1311200041 is an equidigital number, since it uses as much as digits as its factorization.
1311200041 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 24, while the sum is 13.
The square root of 1311200041 is about 36210.4962821555. The cubic root of 1311200041 is about 1094.5181928478.
Adding to 1311200041 its reverse (1400021131), we get a palindrome (2711221172).
The spelling of 1311200041 in words is "one billion, three hundred eleven million, two hundred thousand, forty-one".
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