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131120021111 = 211621421901
BaseRepresentation
bin111101000011101011…
…1001011111001110111
3110112102222110012202012
41322013113023321313
54122013211133421
6140122525034435
712321163535012
oct1720727137167
9415388405665
10131120021111
1150675919612
12214b39b5a1b
13c497c45411
1464bc13a379
15362635195b
hex1e875cbe77

131120021111 has 4 divisors (see below), whose sum is σ = 131741443224. Its totient is φ = 130498599000.

The previous prime is 131120021093. The next prime is 131120021119. The reversal of 131120021111 is 111120021131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 131120021111 - 26 = 131120021047 is a prime.

It is a super-3 number, since 3×1311200211113 (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131120021119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 310710740 + ... + 310711161.

It is an arithmetic number, because the mean of its divisors is an integer number (32935360806).

Almost surely, 2131120021111 is an apocalyptic number.

131120021111 is a deficient number, since it is larger than the sum of its proper divisors (621422113).

131120021111 is an equidigital number, since it uses as much as digits as its factorization.

131120021111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 621422112.

The product of its (nonzero) digits is 12, while the sum is 14.

Adding to 131120021111 its reverse (111120021131), we get a palindrome (242240042242).

The spelling of 131120021111 in words is "one hundred thirty-one billion, one hundred twenty million, twenty-one thousand, one hundred eleven".

Divisors: 1 211 621421901 131120021111