Search a number
-
+
131120112131 is a prime number
BaseRepresentation
bin111101000011101011…
…1100010001000000011
3110112102222121211121022
41322013113202020003
54122013222042011
6140122531020055
712321164364251
oct1720727421003
9415388554538
10131120112131
1150675980a38
12214b3a3a62b
13c497c77988
1464bc1615d1
15362636d8db
hex1e875e2203

131120112131 has 2 divisors, whose sum is σ = 131120112132. Its totient is φ = 131120112130.

The previous prime is 131120112113. The next prime is 131120112139. The reversal of 131120112131 is 131211021131.

Together with previous prime (131120112113) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 131120112131 - 210 = 131120111107 is a prime.

It is a super-2 number, since 2×1311201121312 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (131120112139) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65560056065 + 65560056066.

It is an arithmetic number, because the mean of its divisors is an integer number (65560056066).

Almost surely, 2131120112131 is an apocalyptic number.

131120112131 is a deficient number, since it is larger than the sum of its proper divisors (1).

131120112131 is an equidigital number, since it uses as much as digits as its factorization.

131120112131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 36, while the sum is 17.

Adding to 131120112131 its reverse (131211021131), we get a palindrome (262331133262).

The spelling of 131120112131 in words is "one hundred thirty-one billion, one hundred twenty million, one hundred twelve thousand, one hundred thirty-one".