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1311201130330 = 257132478926497
BaseRepresentation
bin10011000101001001101…
…011010111011101011010
311122100102212020211102001
4103011021223113131122
5132440314442132310
62442205114431214
7163505533500130
oct23051153273532
94570385224361
101311201130330
114660939451a3
1219215273250a
13968518b3700
1447669053750
152419249393a
hex13149ad775a

1311201130330 has 192 divisors, whose sum is σ = 3016549278720. Its totient is φ = 401565745152.

The previous prime is 1311201130303. The next prime is 1311201130339. The reversal of 1311201130330 is 330311021131.

It is a junction number, because it is equal to n+sod(n) for n = 1311201130298 and 1311201130307.

It is not an unprimeable number, because it can be changed into a prime (1311201130339) by changing a digit.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 49471642 + ... + 49498138.

It is an arithmetic number, because the mean of its divisors is an integer number (15711194160).

Almost surely, 21311201130330 is an apocalyptic number.

1311201130330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

1311201130330 is an abundant number, since it is smaller than the sum of its proper divisors (1705348148390).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1311201130330 is a wasteful number, since it uses less digits than its factorization.

1311201130330 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 26673 (or 26660 counting only the distinct ones).

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 1311201130330 its reverse (330311021131), we get a palindrome (1641512151461).

The spelling of 1311201130330 in words is "one trillion, three hundred eleven billion, two hundred one million, one hundred thirty thousand, three hundred thirty".