Base | Representation |
---|---|
bin | 1011111011001110000011… |
… | …0100011010011000000111 |
3 | 1201102111101122212212202011 |
4 | 2332303200310122120013 |
5 | 3204311400034221203 |
6 | 43515324122555051 |
7 | 2522211611161114 |
oct | 276634064323007 |
9 | 51374348785664 |
10 | 13112012023303 |
11 | 41a5855a59786 |
12 | 1579242368a87 |
13 | 7415c3c7c14b |
14 | 3348a651390b |
15 | 17b11821976d |
hex | bece0d1a607 |
13112012023303 has 4 divisors (see below), whose sum is σ = 13228047528048. Its totient is φ = 12995976518560.
The previous prime is 13112012023219. The next prime is 13112012023309. The reversal of 13112012023303 is 30332021021131.
13112012023303 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13112012023303 - 221 = 13112009926151 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13112012023309) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 58017752203 + ... + 58017752428.
It is an arithmetic number, because the mean of its divisors is an integer number (3307011882012).
Almost surely, 213112012023303 is an apocalyptic number.
13112012023303 is a deficient number, since it is larger than the sum of its proper divisors (116035504745).
13112012023303 is a wasteful number, since it uses less digits than its factorization.
13112012023303 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 116035504744.
The product of its (nonzero) digits is 648, while the sum is 22.
Adding to 13112012023303 its reverse (30332021021131), we get a palindrome (43444033044434).
The spelling of 13112012023303 in words is "thirteen trillion, one hundred twelve billion, twelve million, twenty-three thousand, three hundred three".
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