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131120153302001 = 413198052519561
BaseRepresentation
bin11101110100000011001010…
…001010010001001111110001
3122012020222000221001212120012
4131310003022022101033301
5114141233033221131001
61142511433350424305
736422055426524513
oct3564031212211761
9565228027055505
10131120153302001
1138862821275306
1212857b6a062095
135821767721c16
14245436c055bb3
151025b094982bb
hex7740ca2913f1

131120153302001 has 4 divisors (see below), whose sum is σ = 134318205821604. Its totient is φ = 127922100782400.

The previous prime is 131120153301979. The next prime is 131120153302051. The reversal of 131120153302001 is 100203351021131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 65107534517776 + 66012618784225 = 8068924^2 + 8124815^2 .

It is a cyclic number.

It is not a de Polignac number, because 131120153302001 - 210 = 131120153300977 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131120153302051) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1599026259740 + ... + 1599026259821.

It is an arithmetic number, because the mean of its divisors is an integer number (33579551455401).

Almost surely, 2131120153302001 is an apocalyptic number.

It is an amenable number.

131120153302001 is a deficient number, since it is larger than the sum of its proper divisors (3198052519603).

131120153302001 is an equidigital number, since it uses as much as digits as its factorization.

131120153302001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3198052519602.

The product of its (nonzero) digits is 540, while the sum is 23.

The spelling of 131120153302001 in words is "one hundred thirty-one trillion, one hundred twenty billion, one hundred fifty-three million, three hundred two thousand, one".

Divisors: 1 41 3198052519561 131120153302001