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131120155354553 is a prime number
BaseRepresentation
bin11101110100000011001010…
…010010000110010110111001
3122012020222001001221011010122
4131310003022102012112321
5114141233034232321203
61142511433502423025
736422055453133601
oct3564031222062671
9565228031834118
10131120155354553
1138862822447432
1212857b6a891a75
135821767c90251
14245436c42bc01
151025b09751538
hex7740ca4865b9

131120155354553 has 2 divisors, whose sum is σ = 131120155354554. Its totient is φ = 131120155354552.

The previous prime is 131120155354501. The next prime is 131120155354619. The reversal of 131120155354553 is 355453551021131.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 125344415015824 + 5775740338729 = 11195732^2 + 2403277^2 .

It is an emirp because it is prime and its reverse (355453551021131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 131120155354553 - 216 = 131120155289017 is a prime.

It is a super-2 number, since 2×1311201553545532 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (131120155351553) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65560077677276 + 65560077677277.

It is an arithmetic number, because the mean of its divisors is an integer number (65560077677277).

Almost surely, 2131120155354553 is an apocalyptic number.

It is an amenable number.

131120155354553 is a deficient number, since it is larger than the sum of its proper divisors (1).

131120155354553 is an equidigital number, since it uses as much as digits as its factorization.

131120155354553 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 675000, while the sum is 44.

The spelling of 131120155354553 in words is "one hundred thirty-one trillion, one hundred twenty billion, one hundred fifty-five million, three hundred fifty-four thousand, five hundred fifty-three".