Base | Representation |
---|---|
bin | 11101110100000011001110… |
… | …111011010001001001101111 |
3 | 122012020222020111111221012012 |
4 | 131310003032323101021233 |
5 | 114141233214203134120 |
6 | 1142511445324231435 |
7 | 36422060420235266 |
oct | 3564031673211157 |
9 | 565228214457165 |
10 | 131120233255535 |
11 | 38862862414607 |
12 | 12857b9099b57b |
13 | 582177b1670c4 |
14 | 24543789095dd |
15 | 1025b114dd1c5 |
hex | 7740ceed126f |
131120233255535 has 32 divisors (see below), whose sum is σ = 159314472345600. Its totient is φ = 103585784037120.
The previous prime is 131120233255523. The next prime is 131120233255573. The reversal of 131120233255535 is 535552332021131.
It is not a de Polignac number, because 131120233255535 - 26 = 131120233255471 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 131120233255492 and 131120233255501.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1558556642 + ... + 1558640768.
It is an arithmetic number, because the mean of its divisors is an integer number (4978577260800).
Almost surely, 2131120233255535 is an apocalyptic number.
131120233255535 is a deficient number, since it is larger than the sum of its proper divisors (28194239090065).
131120233255535 is a wasteful number, since it uses less digits than its factorization.
131120233255535 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 88631.
The product of its (nonzero) digits is 405000, while the sum is 41.
Adding to 131120233255535 its reverse (535552332021131), we get a palindrome (666672565276666).
The spelling of 131120233255535 in words is "one hundred thirty-one trillion, one hundred twenty billion, two hundred thirty-three million, two hundred fifty-five thousand, five hundred thirty-five".
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