131120233255539 has 48 divisors (see below), whose sum is σ = 209696681731680. Its totient is φ = 78283672542720.

The previous prime is 131120233255523. The next prime is 131120233255573. The reversal of 131120233255539 is 935552332021131.

131120233255539 is a `hidden beast` number, since 1 + 3 + 1 + 12 + 0 + 23 + 32 + 55 + 539 = 666.

It is not a de Polignac number, because 131120233255539 - 2⁴ = 131120233255523 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 131120233255494 and 131120233255503.

It is not an unprimeable number, because it can be changed into a prime (131120233955539) by changing a digit.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 4951584 + ... + 16933949.

It is an arithmetic number, because the mean of its divisors is an integer number (4368680869410).

Almost surely, 2^{131120233255539} is an apocalyptic number.

131120233255539 is a deficient number, since it is larger than the sum of its proper divisors (78576448476141).

131120233255539 is a wasteful number, since it uses less digits than its factorization.

131120233255539 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 21886452 (or 21886449 counting only the distinct ones).

The product of its (nonzero) digits is 729000, while the sum is 45.

The spelling of 131120233255539 in words is "one hundred thirty-one trillion, one hundred twenty billion, two hundred thirty-three million, two hundred fifty-five thousand, five hundred thirty-nine".