Base | Representation |
---|---|
bin | 1011111011001110000110… |
… | …0000010110110011011011 |
3 | 1201102111102110120010210201 |
4 | 2332303201200112303123 |
5 | 3204311411011334003 |
6 | 43515325213523031 |
7 | 2522212111120210 |
oct | 276634140266333 |
9 | 51374373503721 |
10 | 13112023543003 |
11 | 41a58615076a0 |
12 | 15792461a3477 |
13 | 7415c6483638 |
14 | 3348a7c71b07 |
15 | 17b119242b1d |
hex | bece1816cdb |
13112023543003 has 64 divisors (see below), whose sum is σ = 16905615114240. Its totient is φ = 9875370960000.
The previous prime is 13112023542889. The next prime is 13112023543009. The reversal of 13112023543003 is 30034532021131.
It is not a de Polignac number, because 13112023543003 - 217 = 13112023411931 is a prime.
It is a super-2 number, since 2×131120235430032 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13112023543009) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 78210558 + ... + 78378028.
It is an arithmetic number, because the mean of its divisors is an integer number (264150236160).
Almost surely, 213112023543003 is an apocalyptic number.
13112023543003 is a deficient number, since it is larger than the sum of its proper divisors (3793591571237).
13112023543003 is a wasteful number, since it uses less digits than its factorization.
13112023543003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 167840.
The product of its (nonzero) digits is 6480, while the sum is 28.
Adding to 13112023543003 its reverse (30034532021131), we get a palindrome (43146555564134).
The spelling of 13112023543003 in words is "thirteen trillion, one hundred twelve billion, twenty-three million, five hundred forty-three thousand, three".
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