Base | Representation |
---|---|
bin | 10011000101001001110… |
… | …010011111111111110111 |
3 | 11122100102222202211112121 |
4 | 103011021302133333313 |
5 | 132440320432002221 |
6 | 2442205222500411 |
7 | 163505555416021 |
oct | 23051162377767 |
9 | 4570388684477 |
10 | 1311203000311 |
11 | 466094a02136 |
12 | 192153294707 |
13 | 968520b98c9 |
14 | 476693bd011 |
15 | 24192712a41 |
hex | 13149c9fff7 |
1311203000311 has 4 divisors (see below), whose sum is σ = 1311292498552. Its totient is φ = 1311113502072.
The previous prime is 1311203000291. The next prime is 1311203000321. The reversal of 1311203000311 is 1130003021131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1311203000311 - 25 = 1311203000279 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1311203000321) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 44727141 + ... + 44756446.
It is an arithmetic number, because the mean of its divisors is an integer number (327823124638).
Almost surely, 21311203000311 is an apocalyptic number.
1311203000311 is a deficient number, since it is larger than the sum of its proper divisors (89498241).
1311203000311 is an equidigital number, since it uses as much as digits as its factorization.
1311203000311 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 89498240.
The product of its (nonzero) digits is 54, while the sum is 16.
Adding to 1311203000311 its reverse (1130003021131), we get a palindrome (2441206021442).
The spelling of 1311203000311 in words is "one trillion, three hundred eleven billion, two hundred three million, three hundred eleven", and thus it is an aban number.
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