Base | Representation |
---|---|
bin | 1011111011001110000111… |
… | …1101000000101010110011 |
3 | 1201102111102222200202122212 |
4 | 2332303201331000222303 |
5 | 3204311414422221030 |
6 | 43515330042522335 |
7 | 2522212232013521 |
oct | 276634175005263 |
9 | 51374388622585 |
10 | 13112031054515 |
11 | 41a5865778158 |
12 | 15792488063ab |
13 | 7415c7bb3613 |
14 | 3348a8c69311 |
15 | 17b119c28595 |
hex | bece1f40ab3 |
13112031054515 has 4 divisors (see below), whose sum is σ = 15734437265424. Its totient is φ = 10489624843608.
The previous prime is 13112031054487. The next prime is 13112031054527. The reversal of 13112031054515 is 51545013021131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13112031054515 is a prime.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1311203105447 + ... + 1311203105456.
It is an arithmetic number, because the mean of its divisors is an integer number (3933609316356).
Almost surely, 213112031054515 is an apocalyptic number.
13112031054515 is a deficient number, since it is larger than the sum of its proper divisors (2622406210909).
13112031054515 is an equidigital number, since it uses as much as digits as its factorization.
13112031054515 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2622406210908.
The product of its (nonzero) digits is 9000, while the sum is 32.
Adding to 13112031054515 its reverse (51545013021131), we get a palindrome (64657044075646).
The spelling of 13112031054515 in words is "thirteen trillion, one hundred twelve billion, thirty-one million, fifty-four thousand, five hundred fifteen".
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