Base | Representation |
---|---|
bin | 111101000011101101… |
… | …0111010111010110001 |
3 | 110112110001021221200112 |
4 | 1322013122322322301 |
5 | 4122013434000423 |
6 | 140123002031105 |
7 | 12321205053155 |
oct | 1720732727261 |
9 | 415401257615 |
10 | 131121000113 |
11 | 50676428104 |
12 | 214b41a8495 |
13 | c4981c8bcc |
14 | 64bc313065 |
15 | 3626496a78 |
hex | 1e876baeb1 |
131121000113 has 4 divisors (see below), whose sum is σ = 135642413940. Its totient is φ = 126599586288.
The previous prime is 131121000097. The next prime is 131121000139. The reversal of 131121000113 is 311000121131.
It is a happy number.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 35125131889 + 95995868224 = 187417^2 + 309832^2 .
It is a cyclic number.
It is not a de Polignac number, because 131121000113 - 24 = 131121000097 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (131121200113) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2260706870 + ... + 2260706927.
It is an arithmetic number, because the mean of its divisors is an integer number (33910603485).
Almost surely, 2131121000113 is an apocalyptic number.
It is an amenable number.
131121000113 is a deficient number, since it is larger than the sum of its proper divisors (4521413827).
131121000113 is an equidigital number, since it uses as much as digits as its factorization.
131121000113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4521413826.
The product of its (nonzero) digits is 18, while the sum is 14.
Adding to 131121000113 its reverse (311000121131), we get a palindrome (442121121244).
The spelling of 131121000113 in words is "one hundred thirty-one billion, one hundred twenty-one million, one hundred thirteen", and thus it is an aban number.
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