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1311211343402 = 2655605671701
BaseRepresentation
bin10011000101001010010…
…010010100111000101010
311122100110120110201002222
4103011022102110320222
5132440330100442102
62442210121354042
7163506016344632
oct23051222247052
94570416421088
101311211343402
11466099690454
12192156038922
1396853a4b24c
144766a5516c2
152419330eaa2
hex1314a494e2a

1311211343402 has 4 divisors (see below), whose sum is σ = 1966817015106. Its totient is φ = 655605671700.

The previous prime is 1311211343353. The next prime is 1311211343513. The reversal of 1311211343402 is 2043431121131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 955684163281 + 355527180121 = 977591^2 + 596261^2 .

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 327802835849 + ... + 327802835852.

Almost surely, 21311211343402 is an apocalyptic number.

1311211343402 is a deficient number, since it is larger than the sum of its proper divisors (655605671704).

1311211343402 is an equidigital number, since it uses as much as digits as its factorization.

1311211343402 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 655605671703.

The product of its (nonzero) digits is 1728, while the sum is 26.

Adding to 1311211343402 its reverse (2043431121131), we get a palindrome (3354642464533).

The spelling of 1311211343402 in words is "one trillion, three hundred eleven billion, two hundred eleven million, three hundred forty-three thousand, four hundred two".

Divisors: 1 2 655605671701 1311211343402