131121151512133 has 2 divisors, whose sum is σ = 131121151512134. Its totient is φ = 131121151512132.

The previous prime is 131121151512089. The next prime is 131121151512151. The reversal of 131121151512133 is 331215151121131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 90062814160449 + 41058337351684 = 9490143^2 + 6407678^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-131121151512133 is a prime.

It is a super-2 number, since 2×131121151512133² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 131121151512095 and 131121151512104.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131121151516133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65560575756066 + 65560575756067.

It is an arithmetic number, because the mean of its divisors is an integer number (65560575756067).

Almost surely, 2^{131121151512133} is an apocalyptic number.

It is an amenable number.

131121151512133 is a deficient number, since it is larger than the sum of its proper divisors (1).

131121151512133 is an equidigital number, since it uses as much as digits as its factorization.

131121151512133 is an evil number, because the sum of its binary digits is even.

The product of its digits is 2700, while the sum is 31.

The spelling of 131121151512133 in words is "one hundred thirty-one trillion, one hundred twenty-one billion, one hundred fifty-one million, five hundred twelve thousand, one hundred thirty-three".