Base | Representation |
---|---|
bin | 11101110100000100000101… |
… | …101100000010111111000110 |
3 | 122012021001121112022121102221 |
4 | 131310010011230002333012 |
5 | 114141242104403342410 |
6 | 1142512120424322554 |
7 | 36422122244444242 |
oct | 3564040554027706 |
9 | 565231545277387 |
10 | 131121152012230 |
11 | 38863193a98066 |
12 | 128581a861345a |
13 | 58218965ca013 |
14 | 2454424949422 |
15 | 1025b66ec24da |
hex | 774105b02fc6 |
131121152012230 has 32 divisors (see below), whose sum is σ = 238979507929344. Its totient is φ = 51790987801056.
The previous prime is 131121152012183. The next prime is 131121152012273. The reversal of 131121152012230 is 32210251121131.
It is a junction number, because it is equal to n+sod(n) for n = 131121152012195 and 131121152012204.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 37285842 + ... + 40650661.
It is an arithmetic number, because the mean of its divisors is an integer number (7468109622792).
Almost surely, 2131121152012230 is an apocalyptic number.
131121152012230 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
131121152012230 is a deficient number, since it is larger than the sum of its proper divisors (107858355917114).
131121152012230 is a wasteful number, since it uses less digits than its factorization.
131121152012230 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 77938620.
The product of its (nonzero) digits is 720, while the sum is 25.
The spelling of 131121152012230 in words is "one hundred thirty-one trillion, one hundred twenty-one billion, one hundred fifty-two million, twelve thousand, two hundred thirty".
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