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13112121212003 = 111962737422067
BaseRepresentation
bin1011111011001110011101…
…0100111011110001100011
31201102111200021100020111002
42332303213110323301203
53204312111012241003
643515343023142215
72522214405233402
oct276634724736143
951374607306432
1013112121212003
1141a5901656880
121579272a4496b
1374161078c148
143348b6c17639
1517b122ad6a88
hexbece753bc63

13112121212003 has 8 divisors (see below), whose sum is σ = 15056981296320. Its totient is φ = 11292735971880.

The previous prime is 13112121211901. The next prime is 13112121212017. The reversal of 13112121212003 is 30021212121131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 13112121212003 - 218 = 13112120949859 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13112121212033) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 31368710825 + ... + 31368711242.

It is an arithmetic number, because the mean of its divisors is an integer number (1882122662040).

Almost surely, 213112121212003 is an apocalyptic number.

13112121212003 is a deficient number, since it is larger than the sum of its proper divisors (1944860084317).

13112121212003 is a wasteful number, since it uses less digits than its factorization.

13112121212003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 62737422097.

The product of its (nonzero) digits is 144, while the sum is 20.

Adding to 13112121212003 its reverse (30021212121131), we get a palindrome (43133333333134).

The spelling of 13112121212003 in words is "thirteen trillion, one hundred twelve billion, one hundred twenty-one million, two hundred twelve thousand, three".

Divisors: 1 11 19 209 62737422067 690111642737 1192011019273 13112121212003