Search a number
-
+
1311212221103 = 2953144401213
BaseRepresentation
bin10011000101001010010…
…101101011001010101111
311122100110122010022002102
4103011022111223022233
5132440330312033403
62442210152245315
7163506026661551
oct23051225531257
94570418108072
101311212221103
1146609a12a924
121921563a083b
1396853c978b5
144766a6dd4d1
1524193434b88
hex1314a56b2af

1311212221103 has 4 divisors (see below), whose sum is σ = 1311256651848. Its totient is φ = 1311167790360.

The previous prime is 1311212221091. The next prime is 1311212221147. The reversal of 1311212221103 is 3011222121131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1311212221103 - 240 = 211700593327 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1311212221603) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22171076 + ... + 22230137.

It is an arithmetic number, because the mean of its divisors is an integer number (327814162962).

Almost surely, 21311212221103 is an apocalyptic number.

1311212221103 is a deficient number, since it is larger than the sum of its proper divisors (44430745).

1311212221103 is an equidigital number, since it uses as much as digits as its factorization.

1311212221103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 44430744.

The product of its (nonzero) digits is 144, while the sum is 20.

Adding to 1311212221103 its reverse (3011222121131), we get a palindrome (4322434342234).

The spelling of 1311212221103 in words is "one trillion, three hundred eleven billion, two hundred twelve million, two hundred twenty-one thousand, one hundred three".

Divisors: 1 29531 44401213 1311212221103