131121230514145 has 4 divisors (see below), whose sum is σ = 157345476616980. Its totient is φ = 104896984411312.

The previous prime is 131121230514073. The next prime is 131121230514161. The reversal of 131121230514145 is 541415032121131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 60550948539601 + 70570281974544 = 7781449^2 + 8400612^2 .

It is a cyclic number.

It is not a de Polignac number, because 131121230514145 - 2⁷ = 131121230514017 is a prime.

It is a super-2 number, since 2×131121230514145² (a number of 29 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 131121230514145.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13112123051410 + ... + 13112123051419.

It is an arithmetic number, because the mean of its divisors is an integer number (39336369154245).

Almost surely, 2^{131121230514145} is an apocalyptic number.

It is an amenable number.

131121230514145 is a deficient number, since it is larger than the sum of its proper divisors (26224246102835).

131121230514145 is an equidigital number, since it uses as much as digits as its factorization.

131121230514145 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 26224246102834.

The product of its (nonzero) digits is 14400, while the sum is 34.

Adding to 131121230514145 its reverse (541415032121131), we get a palindrome (672536262635276).

The spelling of 131121230514145 in words is "one hundred thirty-one trillion, one hundred twenty-one billion, two hundred thirty million, five hundred fourteen thousand, one hundred forty-five".