Base | Representation |
---|---|
bin | 11101110100000100001110… |
… | …111001001001100110001011 |
3 | 122012021002000021220110102121 |
4 | 131310010032321021212023 |
5 | 114141242413422121443 |
6 | 1142512144022312111 |
7 | 36422126131204204 |
oct | 3564041671114613 |
9 | 565232007813377 |
10 | 131121306442123 |
11 | 38863263185578 |
12 | 12858230288637 |
13 | 58218bc5ba35a |
14 | 245443b2685ab |
15 | 1025b758294ed |
hex | 77410ee4998b |
131121306442123 has 2 divisors, whose sum is σ = 131121306442124. Its totient is φ = 131121306442122.
The previous prime is 131121306442013. The next prime is 131121306442141. The reversal of 131121306442123 is 321244603121131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131121306442123 - 245 = 95936934353291 is a prime.
It is not a weakly prime, because it can be changed into another prime (131121306442223) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65560653221061 + 65560653221062.
It is an arithmetic number, because the mean of its divisors is an integer number (65560653221062).
Almost surely, 2131121306442123 is an apocalyptic number.
131121306442123 is a deficient number, since it is larger than the sum of its proper divisors (1).
131121306442123 is an equidigital number, since it uses as much as digits as its factorization.
131121306442123 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 20736, while the sum is 34.
Adding to 131121306442123 its reverse (321244603121131), we get a palindrome (452365909563254).
The spelling of 131121306442123 in words is "one hundred thirty-one trillion, one hundred twenty-one billion, three hundred six million, four hundred forty-two thousand, one hundred twenty-three".
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