13112155041331 has 2 divisors, whose sum is σ = 13112155041332. Its totient is φ = 13112155041330.

The previous prime is 13112155041299. The next prime is 13112155041343. The reversal of 13112155041331 is 13314055121131.

It is a happy number.

It is a strong prime.

It is an emirp because it is prime and its reverse (13314055121131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13112155041331 - 2⁵ = 13112155041299 is a prime.

It is a super-2 number, since 2×13112155041331² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13112155041293 and 13112155041302.

It is not a weakly prime, because it can be changed into another prime (13112155041361) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6556077520665 + 6556077520666.

It is an arithmetic number, because the mean of its divisors is an integer number (6556077520666).

Almost surely, 2^{13112155041331} is an apocalyptic number.

13112155041331 is a deficient number, since it is larger than the sum of its proper divisors (1).

13112155041331 is an equidigital number, since it uses as much as digits as its factorization.

13112155041331 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5400, while the sum is 31.

The spelling of 13112155041331 in words is "thirteen trillion, one hundred twelve billion, one hundred fifty-five million, forty-one thousand, three hundred thirty-one".