Base | Representation |
---|---|
bin | 111101000011101111… |
… | …1100011111100010011 |
3 | 110112110010120202120011 |
4 | 1322013133203330103 |
5 | 4122014241413343 |
6 | 140123044055351 |
7 | 12321221311141 |
oct | 1720737437423 |
9 | 415403522504 |
10 | 131122216723 |
11 | 50677089173 |
12 | 214b4694557 |
13 | c4985338b4 |
14 | 64bc54c591 |
15 | 362663729d |
hex | 1e877e3f13 |
131122216723 has 2 divisors, whose sum is σ = 131122216724. Its totient is φ = 131122216722.
The previous prime is 131122216703. The next prime is 131122216733. The reversal of 131122216723 is 327612221131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131122216723 - 213 = 131122208531 is a prime.
It is not a weakly prime, because it can be changed into another prime (131122216703) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65561108361 + 65561108362.
It is an arithmetic number, because the mean of its divisors is an integer number (65561108362).
Almost surely, 2131122216723 is an apocalyptic number.
131122216723 is a deficient number, since it is larger than the sum of its proper divisors (1).
131122216723 is an equidigital number, since it uses as much as digits as its factorization.
131122216723 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 6048, while the sum is 31.
Adding to 131122216723 its reverse (327612221131), we get a palindrome (458734437854).
The spelling of 131122216723 in words is "one hundred thirty-one billion, one hundred twenty-two million, two hundred sixteen thousand, seven hundred twenty-three".
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