Base | Representation |
---|---|
bin | 10011000101001011001… |
… | …011000000100110111101 |
3 | 11122100111121102122001001 |
4 | 103011023023000212331 |
5 | 132440342401440212 |
6 | 2442211412050301 |
7 | 163506256553035 |
oct | 23051313004675 |
9 | 4570447378031 |
10 | 1311226202557 |
11 | 4660a700a347 |
12 | 19215b003991 |
13 | 96856b5174b |
14 | 4766c4dc8c5 |
15 | 24194797657 |
hex | 1314b2c09bd |
1311226202557 has 2 divisors, whose sum is σ = 1311226202558. Its totient is φ = 1311226202556.
The previous prime is 1311226202501. The next prime is 1311226202593. The reversal of 1311226202557 is 7552026221131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 971996838201 + 339229364356 = 985899^2 + 582434^2 .
It is a cyclic number.
It is not a de Polignac number, because 1311226202557 - 223 = 1311217813949 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1311226212557) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655613101278 + 655613101279.
It is an arithmetic number, because the mean of its divisors is an integer number (655613101279).
Almost surely, 21311226202557 is an apocalyptic number.
It is an amenable number.
1311226202557 is a deficient number, since it is larger than the sum of its proper divisors (1).
1311226202557 is an equidigital number, since it uses as much as digits as its factorization.
1311226202557 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 50400, while the sum is 37.
The spelling of 1311226202557 in words is "one trillion, three hundred eleven billion, two hundred twenty-six million, two hundred two thousand, five hundred fifty-seven".
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