Base | Representation |
---|---|
bin | 1011111011001111000111… |
… | …1110111101001101100011 |
3 | 1201102112010201202121122102 |
4 | 2332303301332331031203 |
5 | 3204312442300000344 |
6 | 43515412451201015 |
7 | 2522222006013446 |
oct | 276636176751543 |
9 | 51375121677572 |
10 | 13112300000099 |
11 | 41a5993570a33 |
12 | 15793028a616b |
13 | 74163b82a511 |
14 | 3348d287765d |
15 | 17b133650e4e |
hex | becf1fbd363 |
13112300000099 has 2 divisors, whose sum is σ = 13112300000100. Its totient is φ = 13112300000098.
The previous prime is 13112300000017. The next prime is 13112300000113. The reversal of 13112300000099 is 99000000321131.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13112300000099 is a prime.
It is a super-2 number, since 2×131123000000992 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13112300000399) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6556150000049 + 6556150000050.
It is an arithmetic number, because the mean of its divisors is an integer number (6556150000050).
Almost surely, 213112300000099 is an apocalyptic number.
13112300000099 is a deficient number, since it is larger than the sum of its proper divisors (1).
13112300000099 is an equidigital number, since it uses as much as digits as its factorization.
13112300000099 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1458, while the sum is 29.
The spelling of 13112300000099 in words is "thirteen trillion, one hundred twelve billion, three hundred million, ninety-nine", and thus it is an aban number.
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