13112300000113 has 2 divisors, whose sum is σ = 13112300000114. Its totient is φ = 13112300000112.

The previous prime is 13112300000099. The next prime is 13112300000119. The reversal of 13112300000113 is 31100000321131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10094047014769 + 3018252985344 = 3177113^2 + 1737312^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13112300000113 is a prime.

It is a super-2 number, since 2×13112300000113² (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13112300000119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6556150000056 + 6556150000057.

It is an arithmetic number, because the mean of its divisors is an integer number (6556150000057).

Almost surely, 2^{13112300000113} is an apocalyptic number.

It is an amenable number.

13112300000113 is a deficient number, since it is larger than the sum of its proper divisors (1).

13112300000113 is an equidigital number, since it uses as much as digits as its factorization.

13112300000113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 13112300000113 its reverse (31100000321131), we get a palindrome (44212300321244).

The spelling of 13112300000113 in words is "thirteen trillion, one hundred twelve billion, three hundred million, one hundred thirteen", and thus it is an aban number.