Base | Representation |
---|---|
bin | 10011000101001011011… |
… | …010000000011101110100 |
3 | 11122100111212211101010221 |
4 | 103011023122000131310 |
5 | 132440344403243012 |
6 | 2442212032224124 |
7 | 163506335146252 |
oct | 23051332003564 |
9 | 4570455741127 |
10 | 1311230134132 |
11 | 4660a9255186 |
12 | 19216039b044 |
13 | 968578ca119 |
14 | 4766cc435d2 |
15 | 24194cc2507 |
hex | 1314b680774 |
1311230134132 has 12 divisors (see below), whose sum is σ = 2294741176000. Its totient is φ = 655589798136.
The previous prime is 1311230134129. The next prime is 1311230134157. The reversal of 1311230134132 is 2314310321131.
It is a super-2 number, since 2×13112301341322 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1311230134097 and 1311230134106.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6200238 + ... + 6408229.
Almost surely, 21311230134132 is an apocalyptic number.
It is an amenable number.
1311230134132 is a deficient number, since it is larger than the sum of its proper divisors (983511041868).
1311230134132 is a wasteful number, since it uses less digits than its factorization.
1311230134132 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12634470 (or 12634468 counting only the distinct ones).
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 1311230134132 its reverse (2314310321131), we get a palindrome (3625540455263).
The spelling of 1311230134132 in words is "one trillion, three hundred eleven billion, two hundred thirty million, one hundred thirty-four thousand, one hundred thirty-two".
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