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1311230134132 = 222599912608467
BaseRepresentation
bin10011000101001011011…
…010000000011101110100
311122100111212211101010221
4103011023122000131310
5132440344403243012
62442212032224124
7163506335146252
oct23051332003564
94570455741127
101311230134132
114660a9255186
1219216039b044
13968578ca119
144766cc435d2
1524194cc2507
hex1314b680774

1311230134132 has 12 divisors (see below), whose sum is σ = 2294741176000. Its totient is φ = 655589798136.

The previous prime is 1311230134129. The next prime is 1311230134157. The reversal of 1311230134132 is 2314310321131.

It is a super-2 number, since 2×13112301341322 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1311230134097 and 1311230134106.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6200238 + ... + 6408229.

Almost surely, 21311230134132 is an apocalyptic number.

It is an amenable number.

1311230134132 is a deficient number, since it is larger than the sum of its proper divisors (983511041868).

1311230134132 is a wasteful number, since it uses less digits than its factorization.

1311230134132 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12634470 (or 12634468 counting only the distinct ones).

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 1311230134132 its reverse (2314310321131), we get a palindrome (3625540455263).

The spelling of 1311230134132 in words is "one trillion, three hundred eleven billion, two hundred thirty million, one hundred thirty-four thousand, one hundred thirty-two".

Divisors: 1 2 4 25999 51998 103996 12608467 25216934 50433868 327807533533 655615067066 1311230134132