Search a number
-
+
13112310020122 = 26556155010061
BaseRepresentation
bin1011111011001111001010…
…0101001011100000011010
31201102112011102121200112101
42332303302211023200122
53204313002331120442
643515413450034014
72522222160125365
oct276636245134032
951375142550471
1013112310020122
1141a5999195145
12157930611890a
13741640928221
143348d3d250dc
1517b13447ecb7
hexbecf294b81a

13112310020122 has 4 divisors (see below), whose sum is σ = 19668465030186. Its totient is φ = 6556155010060.

The previous prime is 13112310020099. The next prime is 13112310020143. The reversal of 13112310020122 is 22102001321131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 11997002941561 + 1115307078561 = 3463669^2 + 1056081^2 .

It is a self number, because there is not a number n which added to its sum of digits gives 13112310020122.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3278077505029 + ... + 3278077505032.

Almost surely, 213112310020122 is an apocalyptic number.

13112310020122 is a deficient number, since it is larger than the sum of its proper divisors (6556155010064).

13112310020122 is an equidigital number, since it uses as much as digits as its factorization.

13112310020122 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6556155010063.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 13112310020122 its reverse (22102001321131), we get a palindrome (35214311341253).

The spelling of 13112310020122 in words is "thirteen trillion, one hundred twelve billion, three hundred ten million, twenty thousand, one hundred twenty-two".

Divisors: 1 2 6556155010061 13112310020122