Base | Representation |
---|---|
bin | 11101110100000101111011… |
… | …000011101001010111001111 |
3 | 122012021020200202120022100002 |
4 | 131310011323003221113033 |
5 | 114141310123002224012 |
6 | 1142513044045354515 |
7 | 36422222114626163 |
oct | 3564057303512717 |
9 | 565236622508302 |
10 | 131123121133007 |
11 | 38864004563703 |
12 | 12858657b68a3b |
13 | 5821b1b552143 |
14 | 2454570286ca3 |
15 | 1025c2ecd57c2 |
hex | 77417b0e95cf |
131123121133007 has 2 divisors, whose sum is σ = 131123121133008. Its totient is φ = 131123121133006.
The previous prime is 131123121132919. The next prime is 131123121133051. The reversal of 131123121133007 is 700331121321131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131123121133007 - 230 = 131122047391183 is a prime.
It is a super-2 number, since 2×1311231211330072 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131123121133087) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65561560566503 + 65561560566504.
It is an arithmetic number, because the mean of its divisors is an integer number (65561560566504).
Almost surely, 2131123121133007 is an apocalyptic number.
131123121133007 is a deficient number, since it is larger than the sum of its proper divisors (1).
131123121133007 is an equidigital number, since it uses as much as digits as its factorization.
131123121133007 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2268, while the sum is 29.
Adding to 131123121133007 its reverse (700331121321131), we get a palindrome (831454242454138).
The spelling of 131123121133007 in words is "one hundred thirty-one trillion, one hundred twenty-three billion, one hundred twenty-one million, one hundred thirty-three thousand, seven".
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